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nadya68 [22]
3 years ago
14

I need quick help with two math questions, 98 points.

Mathematics
1 answer:
sergey [27]3 years ago
7 0
The first one i think it's B for the second one i think it's D im so sorry if it's wrong hope this helps
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weeeeeb [17]
The answer to this question is c i think
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Which function can be used to find the number of cells of bacteria in the population at time t
Nonamiya [84]

Answer:

db / dt = kb  

this becomes b(t) = Ce^(kt)  

C = 100, the initial population  

P(1) = 420 = 100 e^(1k)  

4.2 = e^k  

ln 4.2 = k  

a) thus, b(t) = 100 e^(t ln 4.2)  

b) b(3) = 100 e^(3 ln 4.2)  

c) growth constant will still be ln 4.2 (constant percentage of populatioin)  

d) 10000 = 100 e^(t ln 4.2)  

100 = e^(t ln 4.2)  

ln 100 = t ln 4.2  

t = ln 100 / ln 4.2

Step-by-step explanation:

6 0
2 years ago
Can someone please explain this?...... ;-;
Serhud [2]

Answer:

Okay I believe it would be c

Step-by-step explanation:

If I'm wrong I'm really sorry...

6 0
3 years ago
Whats the answer for 6n+7-2n-14=5n-1​
12345 [234]

Answer:

Simplifying

6n + 7 + -2n + -14 = 5n + 1

Reorder the terms:

7 + -14 + 6n + -2n = 5n + 1

Combine like terms: 7 + -14 = -7

-7 + 6n + -2n = 5n + 1

Combine like terms: 6n + -2n = 4n

-7 + 4n = 5n + 1

Reorder the terms:

-7 + 4n = 1 + 5n

Solving

-7 + 4n = 1 + 5n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-5n' to each side of the equation.

-7 + 4n + -5n = 1 + 5n + -5n

Combine like terms: 4n + -5n = -1n

-7 + -1n = 1 + 5n + -5n

Combine like terms: 5n + -5n = 0

-7 + -1n = 1 + 0

-7 + -1n = 1

Add '7' to each side of the equation.

-7 + 7 + -1n = 1 + 7

Combine like terms: -7 + 7 = 0

0 + -1n = 1 + 7

-1n = 1 + 7

Combine like terms: 1 + 7 = 8

-1n = 8

Divide each side by '-1'.

n = -8

Simplifying

n = -8

Step-by-step explanation:

6 0
2 years ago
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Math Problem:
Masteriza [31]

Answer:

i dont know

Step-by-step explanation:

I just need points go to this website m a t h w a y for help on any math :)

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3 years ago
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