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Sergio [31]
2 years ago
6

Finding Circumference The radius is cm. v cm OZ The circumference in terms of ais Using 3.14 for A, the approximate circumferenc

e of the circle is cm. d=2cm​
Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
7 0

Answer:7picm Circumference = pi x d Diameter = 7 C = pi x 7 C = 7pi cm.

Step-by-step explanation:

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Help me please!!!!!!! ​
gulaghasi [49]

Answer:

1/9

Step-by-step explanation:

Because

P(both socks are white)= 2/18

4 0
2 years ago
#9 i need help it would really be appreciated
son4ous [18]
For number 9, you know that it makes 40 copies every five minutes. All you have to do is divide 40 by 5.

40 ÷ 5 = 8

It makes 8 copies every minute. 

Your chart can also help you check your answer. It says that it makes 96 copies every 12 minutes and it makes 104 copies every 13 minutes. So multiply 8 by 12 to check it and 8 by 13. 

8 • 12 = 96
8 • 13 = 104

Since those answers match up with the chart, it must be correct.

The photocopier makes 8 copies every minute. Hope that helps!


4 0
2 years ago
Please help me with this math PLEASE
Doss [256]

Answer:

Step-by-step explanation:

  0

r

= 1

6 0
2 years ago
Hey,can you help me please i very need help..
Brut [27]

Answer:

4.71cm

Step-by-step explanation:

5 0
2 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
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