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Jobisdone [24]
3 years ago
11

Select all the expressions which are equivalent to –3(0.15 – 0.2 + 0.25p).

Mathematics
2 answers:
hammer [34]3 years ago
7 0
A: X
B: X
C: X
D: ^_^
E: X
sorry if i messed up
kondor19780726 [428]3 years ago
3 0
We need to see a picture
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Simplify 5(3x-6)-8(3x-7)<br><br> Can someone explain how to do this in English?
Lunna [17]
Remember the distributive property? It goes like x(a+b)=xa+xb... For example 3(6+7)=(3*6)+(3*7)=39
Same here
5(3x-6)-8(3x-7)
do the thing
(15x-30)-(24x-56)
Take parentheses off.
15x-30-24x+56
//WHY PLUS 56 NOT MINUS?
//because there was a minus sign outside the original parentheses, so the signs inside have to be flipped when the parentheses is taken off
//Let's simplify now
15x-24x-30+56
-9x+26
^^The answer!
5 0
3 years ago
Read 2 more answers
Can someone please help me?
aniked [119]

Answer:

cosx=\frac{67}{77} =>x=29.5

Step-by-step explanation:

7 0
3 years ago
The exponent form of √7<br><br>3<br><br>is​
kiruha [24]

Answer

\sqrt{63}

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help!! :) Thank you!
Klio2033 [76]

Let's complete the square

f(x) = x^2 + 6x + 8

y = x^2 + 6x + 8

y-8 = x^2 + 6x

y-8+9 = x^2+6x+9 .... see note below

y+1 = (x+3)^2

y = (x+3)^2-1

note: I added 9 to both sides due to taking half of the 6, and then squaring that result.

We'll restrict x such that x \ge -3 to ensure that this function is one-to-one.

Now we need to swap x and y, and solve for y to get the inverse

y = (x+3)^2 - 1

x = (y+3)^2 - 1

x+1 = (y+3)^2

(y+3)^2 = x+1

y+3 = sqrt(x+1)

y = sqrt(x+1)-3

g(x) = sqrt(x+1)-3     is the inverse

The graph is shown below. The original function is in red. The inverse is in blue. The inverse is the result of reflecting the red curve over the dashed line y = x. So this explains why x and y swap places. Consequently, the domain and range also swap as well.

4 0
3 years ago
A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth
Lorico [155]
First setup the system of equations for the given case.
Let sandwich=x
and delivery fee =y
Equations are:
4x+y=33 Equation 1
8x+y=61 Equation 2
Subtract equation 1 from 2.
4x=28
x=7
Now substitute value of x in equation 1.
4(7)+y=33
28+y=33
y=5

So cost of single sandwich=$7 and Delivery fee=$5

Now cost of  12 sandwiches:
12x+y=85
Put y=5
12x+5=85
12x=80
x=6.67 which is less than 7. So, They are not able to get 12 sandwiches for $85.
6 0
3 years ago
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