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Ray Of Light [21]
2 years ago
8

PLS help will choose brainliest!

Mathematics
1 answer:
Reptile [31]2 years ago
8 0

Step-by-step explanation:

Explained in the picture

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HELP PLZ PLZ PLZ!!! Maths
TiliK225 [7]

these inequalities can be solved just like equations

a. x - 7 > 25

+ 7 +7 x > 32the number line would have a filled in circle at 32 with an arrow pointing to the rightb. x - 8 < 5+8 +8x < 13 the number line would have an empty circle at 13 with an arrow pointing to the leftc.x + 11 > 23 - 11 - 11x > 12the number line would have an empty circle at 12 with an arrow pointing to the rightd. x + 12 < 6 - 12 - 12 x < -6the number line would have a filled in circle at -6 with an arrow pointing to the lefta. 21 < x + 18 -18 -18 3 < xx > 3b. 16 < x - 7 + 7 + 7 23 < x x > 23c. 12 > x - 7 + 7 + 7 19 > x x < 19d. 29 < x + 53 - 53 - 53 -24 < x x > -24e. 15 > x + 19 -19 -19 -4 > x x < -4f. 35 > x - 8 +8 +8 43 > x x < 43g. -6 < x - 18 +18 +18 12 < x x > 12h. -15 < x - 2 + 2 +2 -13 < x x > -13
3 0
3 years ago
An inverted pyramid is being filled with water at a constant rate of 25 cubic centimeters per second. The pyramid, at the top, h
UNO [17]

Answer:

\frac{225}{16} cm/s

Step-by-step explanation:

We are given that

\frac{dV}{dt}=25cm^3/s

Side of base=4 cm

l=w=4 cm

Height,h=12 cm

We have to find the rate at which the water level rising when the water level is 4 cm.

Volume of pyramid=\frac{1}{3}lwh=\frac{1}{3}l^2h

\frac{l}{h}=\frac{4}{12}=\frac{1}{3}

l=\frac{1}{3}h

Substitute the value

V=\frac{1}{27}h^3

Differentiate w.r.t t

\frac{dV}{dt}=\frac{3}{27}h^2\frac{dh}{dt}

Substitute the values

25=\frac{1}{9}(4^2)\frac{dh}{dt}

\frac{dh}{dt}=\frac{25\times 9}{16}=\frac{225}{16} cm/s

5 0
3 years ago
A line that crosses segment at right angles while dividing the segment in half is called
iren [92.7K]

The correct answer is:

A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>

Step-by-step explanation:

A bisector is a line that divides a line segment in two equal parts. A perpendicular bisector is a line that is perpendicular to given line segment and passes through the mid-point of the line segment. It can also be said as that the line perpendicular to a line segment that divides the lines in half is called the perpendicular bisector.

The correct answer is:

A line that crosses segment at right angles while dividing the segment in half is called <u>a perpendicular bisector</u>

Keywords: Perpendicular, bisector

Learn more about geometry at:

  • brainly.com/question/2115122
  • brainly.com/question/2116906

#LearnwithBrainly

8 0
2 years ago
Daniel works at a nearby electronics store. He makes a commission of 15% on everything he sells. If he sells a laptop for $293.0
nata0808 [166]
$43.95 (293.00-15%=$43.95)

7 0
2 years ago
Read 2 more answers
Part A Assume the ball passes through the points ( 3 , 8 ) , ( 5 , 20 3 ) , and ( 6 , 5 ) . Use this data to set up a system of
Zepler [3.9K]

The three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

<h3>What is a solution to a system of equations? (SOLUTION GRAPHICALLY)</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and like all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none).

The general equation of parabola is given as,

y = ax² + bx + c

The first point is (3,8), therefore, we can write,

8 = a(3)² + b(3) + c

9a + 3b + c = 8

The second point is (5, 20/3), therefore, we can write,

20/3 = a(5)² + b(5) + c

75a + 15b + 3c = 20

The third point is (6, 5), therefore, we can write,

5 = a(6)² + b(6) + c

36a + 6b + c = 5

Hence, the three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

Learn more about System of equations:

brainly.com/question/26254258

#SPJ1

6 0
2 years ago
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