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Temka [501]
2 years ago
11

What is the number when 10 is subtracted from the sum of 20 and product of 2 and 10 divided by 4​

Mathematics
1 answer:
Reil [10]2 years ago
8 0

Answer:

15

Step-by-step explanation:

((10x2)/4)+20-10

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P(x)=12x-5x+20 solve for p(x)
Alexeev081 [22]

Answer:

Step-by-step explanation:

p(x)=7x+20

p=7x/x + 20/x

answer   p=7+20/x

I hope its helpful.

4 0
3 years ago
The median number of goals scored by 7 players in a certain soccer season is 5. The range of the number of goals scored by those
anygoal [31]
The range cannot be 4 if the median is 5.
False.
6 0
3 years ago
Read 2 more answers
How do i find x in #21
Cerrena [4.2K]
In quadrilaterals inscribed in circles, the sum of opposite angles=180 degrees. so, x+134=180
8 0
3 years ago
Find the measure of each angle
Nesterboy [21]
Let's solve this problem step-by-step.

To begin with, it is important to establish the following formula:

Angle sum of all triangles = 180°

Using this formula as well as the values of two out of three of the angles given, we can identify the value of the unknown angle as displayed as the following:

Let the unknown angle = x

Make (x) the subject as displayed as the following:

Angle sum of all triangles = 180°
180 = x + 63 + 59
x = 180 - 63 - 59
x = 58°

Therefore, the measure of each of the angles is as follows:

63°
59°
58°
6 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
3 years ago
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