4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ
hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)
Answer: 7 Per Plain wrapping paper, and 8 Per Shiny wrapping paper
Hope this helps :)
36 divided by 3 plus 90 divided by 3 I think I hope this helps u
5:17 Am
11:32 + 5 is 4. 32 min plus 45 is 77-60 (which is an hour) is 17 minutes.
The sum of interior angels of a pentagon is 550
