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2 years ago

A

Mathematics

1 answer:

gavmur [86]2 years ago

8 0

I don't know sorry I tried to work it but didn't work

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Is the following relation a function? x y 1 4 −1 −2 3 10 5 16

Sergio [31]

No , because it doesn’t have a pattern . For example put the numbers in a chart 1+3 = 4 , -1+3 =2 , 3+7=10 , 5+11=16 , there’s no pattern

3 0

3 years ago

Solve using the Zero Product Property. What is one solution for x? (x – 5) (x + 1) =0

andriy [413]

The answer would be 2.) 5

(5-5) = 0 (5+1) = 6

0x6= 0

4 0

3 years ago

Using the simple random sample of weights of women from a data set, we obtain these sample statistics: nequals45 and x overbar

Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : $n=45$

$\overline{x}=148.79\text{ lb}$

$\sigma=31.37\text{ lb}$

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = $\mu=148.79\text{ lb}$

b) The confidence interval for the population mean is given by :-

$\mu\ \pm E$ , where E is the margin of error.

Formula for Margin of error :-

$z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Significance level : $\alpha=1-0.90=0.1$

Critical value : $z_{\alpha/2}=z_{0.05}=\pm1.645$

Margin of error : $E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69$

Now, the 90% confidence interval for the population mean will be :-

$148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)$

Hence, the 90% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0

3 years ago

Answer all for brainliest

Marizza181 [45]

Answer:

rrnw

Step-by-step explanation:

5 0

2 years ago

Need help with 13 asap

Whitepunk [10]

I’m hoping you are talking about:
Factor -1/2 out of -1/2x + 6
If so then the answer is
-1/2(x-3)

4 0

3 years ago