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2 years ago

Which table of values goes with the equation y = x 2 - 2x + 3?

Mathematics

1 answer:

vichka [17]2 years ago

8 0

Answer: A

Step-by-step explanation:

when you substitute all the x values in the table of values from A, you get all the y values in the table

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Courtneys belong to a health club that charges monthley fee of $25, plus $80 to join

densk [106]

PART A: the function is
Y=25x+80
X represents the number of months.

PART B:
You plug in 6 for X
(25*6)+80=230

5 0

2 years ago

Please help fast need it by today

KiRa [710]

6. It is asking you to find the surface area for this one:

1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters

The volume of the cylinder has to be 0.0154m^3.

V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m

Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2

Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.

C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2

Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2

You will need 0.47m^2 of sheet metal to make this cylinder.

7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.

Everything:
Watch out for units, since the diameter is in mm and the length is in cm.

r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3

Graphite:

r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3

5.34 - 0.11 = 5.23cm^3

8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:

r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3

153.94*250 = 38484.51cm^3 of soup needed.

I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day

3 0

2 years ago

Solve the given equation over the interval [0, 2π): cot^2 x − cot x.

AlekseyPX

$45^o, 90^o, 225^o, 270^o$
$\frac{ \pi }{4} , \frac{ \pi }{2} , \frac{5 \pi }{4} , \frac{3 \pi }{2}$

8 0

3 years ago

Point A of rectangle ABCD is located at coordinates (3,7). If rectangle ABCD is translated down 7 and left 5, what are the new c

uranmaximum [27]

Answer:

The new co-ordinates are A¹ ( -2 , 0)

Step-by-step explanation:

Step(i):-

Point A of rectangle ABCD is located at coordinates (3,7).

Type of transformation change of co-ordinate point

Vertical translation up 'd' units (x, y)→ (x, y +d)

Vertical translation down 'd' units (x, y)→ (x, y -d)

Horizontal translation left 'C' units (x, y)→ (x - c , y)

Horizontal translation right 'C' units (x, y)→ (x + c , y)

Step(ii):-

Given rectangle ABCD is translated down 7 and left 5

Given Point A(3 ,7)

Vertical translation down '7' units t

The new co-ordinate A¹ ( 3 , 7-7)→ A¹( 3, 0) and Horizontal translation left ''5' units

Now the new co-ordinates are A¹ ( 3-5 , 7-7)

Final answer:-

The new co-ordinates are A¹ ( -2 , 0)

7 0

3 years ago

Consider the following 8 numbers, where one labelled

AlladinOne [14]

<h3>Answers: x = -17 and x = 64</h3>

====================================================

Explanation

Consider three scenarios:

A) The value of x is the smallest of the set (aka the min)
B) The value of x is the largest of the set (aka the max)
C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

56+x= 39

x = 39-56

x = -17 which is one possible answer

--------------------

If instead we go with scenario B, then x is the max and 8 is the min

range = max - min

56 = x - 8

56+8 = x

64 = x

x = 64 is the other possible answer

--------------------

Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.

Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.

7 0

2 years ago