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2 years ago

12

Please Help!!

1 answer:

Margaret [11]2 years ago

8 0

That’s literally the easy problem ever

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2(x + 4)= 2(-8 - x) - 2x<br> Plz explain or show how u got the answer

Andrews [41]

Answer: x=-4

Step-by-step explanation:

See attachment

5 0

4 years ago

Please help answer :)

Umnica [9.8K]

Answer:

Step-by-step explanation:

1. You just plot the points

2. To plot the line you have to find the slope and y-intercept

Slope = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ = $\frac{30-15}{4-2}$ = $\frac{15}{2}$

Slope = $\frac{15}{2}$

Y-intercept = $y-y_{1}=m(x-x_{1} )$

Y-intercept: y - 15 = $\frac{-15}{2}$ (x - 2)

y - 15 = $\frac{-15}{2}x$ + 15

Add 15 to both sides

y = $\frac{-15}{2}$ x + 30 this is the equation of the line.

So you start with the starting point and then the slope!

5 0

4 years ago

3 = m/12<br>What is m?<br><br>It is for math

JulsSmile [24]

Answer:

m is equal to 36.

Step-by-step explanation:

To get rid of division, all you need to do is multiply both sides of the equation by the denominator, which is 12 in this case:

$3 = \frac{m}{12}\\\\3 \times 12 = \frac{m}{12} \times 12\\\\36 = m$

So m is equal to 36

3 0

3 years ago

Solve for x<br> X=In sqrt e

sesenic [268]

Step-by-step explanation:

e = 2.7182818 so you can just plug that in to your calculator and solve like normal

4 0

3 years ago

A 2000-gallon metal tank to store hazardous materials was bought 15 years ago at cost of $100,000. What will a 5,000-gallon tank

harkovskaia [24]

Answer:

The value is $P_o = \$ 561958.9$

Step-by-step explanation:

From the question we are told that

The capacity of the metal tank is $C = 2000 \ gallon$

The duration usage is $t = 15\ years \ ago$

The cost of 2000-gallon tank 15 years ago is $P = \$100,000$

The capacity of the second tank considered is $C_1 = 5,000$

The power sizing exponent is $e = 0.57$

The initial construction cost index is $u_1 = 180$

The new construction after 15 years cost index is $u_2 =600$

Equation for the power sizing exponent is mathematically represented as

$\frac{P_n}{P} = [\frac{C_1}{C} ]^{e}$

=> Here $P_n$ is the cost of 5,000-gallon tank as at 15 years ago

So

$P_n = [\frac{5000}{2000} ] ^{0.57} * 100000$

$P_n = \$168587.7$

Equation for the cost index exponent is mathematically represented as

$\frac{P_o}{P_n} = \frac{u_2}{u_1}$

Here $P_o$ is the cost of 5,000-gallon tank today

So

$\frac{P_o}{168587.7} = \frac{600}{180}$

=> $P_o = \frac{600}{180} * 168587.7$

=> $P_o = \$ 561958.9$

8 0

4 years ago