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IrinaK [193]
3 years ago
13

As a construction manager, you are asked to build a new road, which crosses the point (3,0). There is another road already built

, which can be expressed as y=4x-2. You are asked to build your road such as that it crosses this road at a perpendicular angle. Find the correct value for a and b in the following equation of your road. A=x B=y
Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

is their any way I can get some more info on this problem


Step-by-step explanation:


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What is the sum of a common geometric series if the first term is 8 and the common ratio is 1/2?
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Step-by-step explanation:

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3 years ago
A road perpendicular to a highway leads to a farmhouse located d miles away. An automobile traveling on this highway passes thro
pshichka [43]

Answer:

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

Step-by-step explanation:

A road is perpendicular to a highway leading to a farmhouse d miles away.

An automobile passes through the point of intersection with a constant speed \frac{dx}{dt} = r mph

Let x be the distance of automobile from the point of intersection and distance between the automobile and farmhouse is 'h' miles.

Then by Pythagoras theorem,

h² = d² + x²

By taking derivative on both the sides of the equation,

(2h)\frac{dh}{dt}=(2x)\frac{dx}{dt}

(h)\frac{dh}{dt}=(x)\frac{dx}{dt}

(h)\frac{dh}{dt}=rx

\frac{dh}{dt}=\frac{rx}{h}

When automobile is 30 miles past the intersection,

For x = 30

\frac{dh}{dt}=\frac{30r}{h}

Since h=\sqrt{d^{2}+(30)^{2}}

Therefore,

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+(30)^{2}}}

\frac{dh}{dt}=\frac{30r}{\sqrt{d^{2}+900}}

3 0
3 years ago
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