Answer:
B) 102 units
Step-by-step explanation:
The diagonals of a parallelogram bisect each other. This means ...
BE = ED
3 -9x = -8x +14
-11 = x . . . . . . . . . . . . add 9x -14
BE = 3 -9x = 3 -9(-11) = 3 +99
BE = 102 units
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation:
The answer is A. h + 3s = 35 and 2h + s = 20
Your answer would be C. 6.07 × 10^24.
This is because to add numbers in standard form, we need to get their (×10^x) to be the same, as in, we need to get 7 × 10^22 to be [value] × 10^24.
To convert ×10^22 to ×10^24, we need to divide 7 by 100, as 0.07 × 10^24 = 7 × 10^22.
Now that we have them both with the same power, we can add 6 to 0.7 to get 6.07 × 10^24.
I hope this helps! Let me know if you have any questions because my explanation was a bit strange :)
Answer:
can be written as the single logarithm:

Step-by-step explanation:
Start by using in both terms of the expression the property of logarithm of a power that states:

so we recognize that the factor that multiplies each logarithmic expression, can be understood as the power of the argument of the function logarithm:

Then we use the property of logarithm of a product which states that:

So now we recognize the expression:

as the logarithm of the product:

which is finally a single logarithm as requested.