One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
Answer:
The jar has 32 dimes and 18 quarters
Step-by-step explanation:
<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>
<u> and </u>
<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:
Dimes ( ) = $0.10
Quarters( ) = $0.25
Total Value = $7.70
Total Coins = 50
Now let us set up our system of equations as:
Eqn.(1)
Eqn.(2)
Lets take Eqn.(2) and rerrange it to solve for as:
Eqn.(3)
Now lets plug this, in Eqn.(1) so we get the value of as:
Plugging in 
back in Eqn.(3) we finally have:
Thus we conclude that in the jar the coins are:
Dimes ( ) 
Quarters( ) 
Answer:
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Step-by-step explanation-6790985
Answer:
1/4
Step-by-step explanation:
There are 4 equal sized sections, and 2 sections that are twice the size of the others ( 2*2=4), for a total of 8 sections
The section with a 6 in it is a double size section so it counts as 2 sections
P(6) =number of sections with a 6/ total sections
=2/8
=1/4
