The key is Esther travelled the same distance - x - in both her morning and evening commute.
45(time she took in the morning, or p) = x
30(time she took in the evening, or q) = x
Therefore 45(p) = 30(q), or divide both sides by 5 and get 9(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.
Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.
Therefore 9(60-q) = 6q or 540-9q = 6q. So 540 = 15q, which makes q = 36. If q = 36, then by (p+q)=60, p (the time she took in the morning) must equal 24.
45 miles per hour, her speed in the morning, times (24/60) hours, her time, makes 18 miles travelled in the morning. If you check, 30 miles per hour times (36/60) hours also makes 18 miles in the evening.
<span>Hope that makes a little sense. And I also hope it's right</span>
Answer:
She worked 12 hours for the week
Step-by-step explanation:
Given that :
Hours worked :
Mondays = 40 hours
Tuesdays = 8 hours
If 1/4 of regular hours was worked in a certain week, the number of hours worked that week can be calculated thus ;
1/4 (Monday hours + Tuesday hours)
1/4(40 + 8)
(1/4 * 40) + (1/4 * 8)
10 + 2
= 12 hours
There’s an invisible 1 in front of the minus sign and an invisible 1 in front of the variable.
-1(r+4)=-3 —> -1 times 1r = -1r. -1 times 4 = -4
Multiply inside the parentheses.
-1r-4=-3
Now add 4 to both sides.
-1r-4=-3
+4=+4
-1r = 1
Now divide
R= -1
Answer:
work is shown and pictured
