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kicyunya [14]
3 years ago
10

Write an equation of the line below.

Mathematics
1 answer:
kondaur [170]3 years ago
6 0

The equation of the given line above is y=3x-1. The slope of the line is 3/1 (3x) and the y-intercept which is where the line crosses the y-axis is (0,-1) When you plug these parameters into the equation you will get the equation y=3x-1

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Draw the translation.
shutvik [7]

Answer:

G(-3,-2)   W(-3,0)   E(1,1)

Step-by-step explanation:

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3 years ago
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If b is the measure of an acute angle and cos b = 0.75, then:
Marina CMI [18]

Answer:

option (2)

Step-by-step explanation:

Using the cofunction identity

cosx = sin(90 - x) , then

cosb = sin(90 - b) = 0.75

3 0
3 years ago
Assume that p is a relation that contains the points (3, -4). What other point must be included in the relation if p is:1. symme
AlladinOne [14]

The point needed for the relation is P(x,y) = (3, 4) if P and P' are symmetric about the x-axis.

The point needed for the relation is P(x,y) = (-3, -4) if P and P' are symmetric about the y-axis.

In this exercise we are supposed to determine the coordinates of a point P under an assumption of rigid transformation. Now, we must use the following <em>symmetry</em> transformations:

Reflection about the x-axis

S'(x,y) = S(x,y) - 2\cdot (0, s_{y}) (1)

Reflection about the y-axis

S'(x,y) = S(x,y) - 2\cdot (s_{x}, 0) (2)

Where:

  • S(x,y) - Original point.
  • S' (x,y) - Reflected point.
  • s_{x}, s_{y} - Coordinates of point S.

If we know that P'(x,y) = (3, -4), the coordinates for each reflection are, respectively:

Reflection about the x-axis

P(x,y) = (3,-4) - 2\cdot (0, -4)

P(x,y) = (3, 4)

P(x,y) = (3, 4) if P and P' are symmetric about the x-axis.

Reflection about the y-axis

P(x,y) = (3, -4) - 2\cdot (3, 0)

P(x,y) = (-3, -4)

P(x,y) = (-3, -4) if P and P' are symmetric about the y-axis.

We kindly invite to see this question on rigid transformations: brainly.com/question/18613109

8 0
2 years ago
How much more Ted saved
marishachu [46]

He saves $20 i did this and i got the right answer. hope this helps mark me as brainliest




8 0
3 years ago
Given: EGEF = JK<br><br> Prove: FG = HJ <br><br> PLEASE HELP ASP
Thepotemich [5.8K]

Answer:

Done.

Step-by-step explanation:

EG = EF + <u>FG</u>

HK = <u>HJ</u> + JK

We have: EG = HK and EF = JK => <u>FG</u> = <u>HJ</u>

4 0
3 years ago
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