Answer:
8y^2 + 3xy + 2y^2 - 4xy
8y^2 + 2y^2 + 3xy - 4xy
10y^4 - 1xy
Step-by-step explanation:
8y^2 + 3xy + 2y^2 - 4xy
8y^2 + 2y^2 + 3xy - 4xy
10y^4 - 1xy
If those are the possible answers i'm pretty sure you need to have a group of numbers you extract the mean from for example form the numbers 56, 77, 65, 87, and 99 the mean of the numbers would be 77 so once i have those we can figure it out
(8j3 - 5j2 - 5) - (6j3 - 12j2 + 8j - 7) =
(8j3 - 6j3) - (5j2 - 12j2) - 8j - (5-7) =
2j3 - (-7j2) - 8j - (-2) =
2j3 + 7j2 - 8j + 2
The correct answer is D. 2j3 + 7j2 - 8j + 2
