<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:
again
keep square root alone
solve subtraction of 7-2
Squaring on both side
2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
Y=kx
35=7k
35/7=k
k=5
y=5x
y=5×11
y=55
Answer: The functions values are greater than 0 over the interval.
Step-by-step explanation:
To tell if a function is positive over a given interval, see if it's below the x-axis or if it's under (since the x-axis represents 0).
- If it's below, it's less than zero.
- If it is above, it's greater than zero.
If the interval is above the x-axis, it's positive (greater), and if it's below, it's negative (less).
Well you need to find a common denominator which 30 is the closest one. 5/6 becomes 25/30, 9/10 becomes 27/30. 27/30+ 25/30 = 52/30. To simplify that you divide by 2 to get 26/15. It is no longer divisible to a whole number after that point.
Answer:
a
Step-by-step explanation:
