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sergeinik [125]
2 years ago
14

I need some help with this monomial.... 15a^16b^11/(3a^4b^2)^3

Mathematics
1 answer:
Serga [27]2 years ago
8 0

Answer:

\frac{5a^4b^5}{9}

Step-by-step explanation:

\frac{15a^1^6b^1^1}{(3a^4b^2)^3}

=\frac{15a^1^6b^1^1}{27a^1^2b^6}

=\frac{15a^4b^5}{27}

=\frac{5a^4b^5}{9}

Answer = =\frac{5a^4b^5}{9}  

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