Answer:
The length of the fence needed to surround this garden is 188 meters.
Step-by-step explanation:
Given : A fence is guarding off a vegetable garden in the form of a rectangle. It has one side that is 10 m greater than the other side.
To find : The length of the fence needed to surround this garden if the area of the vegetable garden is 2184 m² ?
Solution :
Let the one side of rectangle be 'x'.
Then the other side is 'x+10'.
The area of the rectangle is 2184 m²,
i.e. 
Solve by middle term split,
Reject negative value,
The side of the rectangle is 42 m.
The other side is 42+10=52 m
The perimeter of the rectangle is 
Therefore, the length of the fence needed to surround this garden is 188 meter.
ΔRSP ≅ ΔQSP by SAS. Therefore, PR ≅ PQ by CPCTC theorem.
<h3>What is the CPCTC Theorem?</h3>
If two triangles are congruent, the CPCTC theorem states that all corresponding parts of the two triangles would also be congruent to each other.
Since S is the midpoint of QR, therefore, RS ≅ QS (one pair of congruent sides)
∠RSP ≅ ∠QSP [right angles] (one pair of congruent included angles)
SP ≅ SP based on the reflexive property (one pair of congruent sides)
Therefore, ΔRSP ≅ ΔQSP by SAS.
Conclusively, PR ≅ PQ by CPCTC theorem.
Learn more about the CPCTC theorem on:
brainly.com/question/6076251
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A) x + y = -80
B) 3x = y
x + 3x = -80
4x = -80
x = -20
y = -60
Given, Sylvie needs $110 for a concert ticket.
Sylvie has $16.
Her hourly earnings = $h
Sylvie is working 10 hours at her job.
She is getting in 1 hour = $h
So, 10 hours she will get = $ = $
So the total amount she has now = $16 + $(10h) = $()
So we can write the equation as,
110=16+10h
We can move 16 to the left side also. 16 is added to the right side. We can move it by using reverse operation of addition. Reverse operation of addition is subtraction. So we will subtract 16 from both sides. Subtracting 16 we will get,
110-16=16+10h-16
110-16=10h
We have got the required answer.
To find Sylvie's hourly income the correct options are option A and option D.
Using Excel formulas
=LARGE(A1:A20, 1)/COUNT (A1:A20)
Count (Ai:An) Function that allows to count the total number of values in a cells range between Ai and An that contain only numbers.
Large (Ai:An, k) Function that allows to find the value of the largest number in a cells range between Ai and An, the number k determine the k-th largest value
