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anyanavicka [17]

3 years ago

11

A lake was closed because of an accidental pesticide spill. The concentration of the pesticide after the spill was 848 parts per

million. Each day the water is tested, and the amount of pesticide is found to be about 75% of what was there the day before. Do you think the lake will ever be completely free of the pesticide? Explain.

2 answers:

e-lub [12.9K]3 years ago

8 0

Hence lake will never be free of pesticides

DochEvi [55]3 years ago

5 0

Answer:

Step-by-step explanation:

$a_{n}=a_{1}r^{n-1}\\0=848(0.75)^{n-1}\\or~(0.75)^{n-1}=0\\0.75$

$or~n \rightarrow 1+\infty\\or~n \rightarrow \infty$

Hence lake will never be free of pesticide.

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What is the GCF of 24,44,52

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The greatest common factor (GCF) of 24, 44, and 52 is: 4

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Factors of 44: 1, 2, 4, 11, 22
Factors of 52: 1, 2, 4, 13

The common factors between them are 1, 2, and 4, but 4 is the greatest, making it the GCF.

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3 years ago

A price of a motorcycle is Rs 175000. The year rate of deprecation is 4%. Find the price of motorcycle after 3 years

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1 year ago

Degree 3 polynomial with zeros 4, 6, and -2.

hjlf

Answer:

Step-by-step explanation:

hello :

an Degree 3 polynomial with zeros 4, 6, and -2 is :

f(x) = (x-4)(x-6)(x+2)

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2 years ago

The function has three factors. Two of these factors

borishaifa [10]

The values of a and b will be -2 and 22 while the other factor in the function is x - 3/2.

<h3>How to illustrate the function?</h3>

The function is given as:

f(x) = ax³ - x² + bx - 24.

Since (x - 2) and (x - 4) are the factors, they will give functions of 8a + 2b = 28 and -16a - b = 10.

This will be solved by elimination method and the values of a and b will be -2 and 22.

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1 year ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

2 years ago