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777dan777 [17]
2 years ago
9

Triangle ABC has angle measures as shown.

Mathematics
2 answers:
Readme [11.4K]2 years ago
6 0
X = 6 . I did this class
pychu [463]2 years ago
5 0

The sum of the angles of any triangle is 180 degrees, so we get the equation:

     (70)+(60)+(8x+2)=180\\8x+132=180\\8x=48\\x = 6

x = 6

Hope that helps!

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PLEASE HELP, ITS DUE IN 2 MINUTES, I'LL GIVE 25 POINTS
andreyandreev [35.5K]

Step-by-step explanation:

x+13⁰+10x+13⁰+2x-2⁰= 180⁰

13x= 180-24

13x=156

x = 12⁰

now angle Q = 10x+13⁰

= 10(12)+13= 120+13

= 133⁰

5 0
3 years ago
804.25 CM ROUNDED TO THE NEAREST HUNDRETH
Y_Kistochka [10]
It is 804.25

2 is in the tenths place and then 5 is hundredths place
4 0
3 years ago
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Bobbie has 100 more followers than Debora. Write an expression that
alukav5142 [94]

Answer: x + 100

Step-by-step explanation:

From the question, we are told that Bobbie has 100 more followers than Debora and x is used to represent the number of followers that Debora has.

The expression that shows the number of followers Bobbie has will be the number of followers that Debora has plus 100. This will be :

= x + 100

4 0
3 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
If there are 16 ounces in a pound and a baby weighs 10 pounds, how many ounces does the baby weigh?
emmasim [6.3K]
16 times 10 is 160 so 160 ounces
5 0
3 years ago
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