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umka2103 [35]
2 years ago
6

Someone please help me

Mathematics
1 answer:
neonofarm [45]2 years ago
8 0

Answer:

I think the answer is A

Step-by-step explanation:

I'm not sure tho

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How do I find the integral<br> ∫10(x−1)(x2+9)dxint10/((x-1)(x^2+9))dx ?
defon
\int\frac{10}{(x-1)(x^2+9)}\ dx=(*)\\\\\frac{10}{(x-1)(x^2+9)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+9}=\frac{A(x^2+9)+(Bx+C)(x-1)}{(x-1)(x^2+9)}\\\\=\frac{Ax^2+9A+Bx^2-Bx+Cx-C}{(x-1)(x^2+9)}=\frac{(A+B)x^2+(-B+C)x+(9A-C)}{(x-1)(x^2+9)}\\\Updownarrow\\10=(A+B)x^2+(-B+C)x+(9A-C)\\\Updownarrow\\A+B=0\ and\ -B+C=0\ and\ 9A-C=10\\A=-B\ and\ C=B\to9(-B)-B=10\to-10B=10\to B=-1\\A=-(-1)=1\ and\ C=-1

(*)=\int\left(\frac{1}{x-1}+\frac{-x-1}{x^2+9}\right)\ dx=\int\left(\frac{1}{x-1}-\frac{x+1}{x^2+9}\right)\ dx\\\\=\int\frac{1}{x-1}\ dx-\int\frac{x+1}{x^2+9}\ dx=\int\frac{1}{x-1}-\int\frac{x}{x^2+9}\ dx-\int\frac{1}{x^2+9}\ dx=(**)\\\\\#1\ \int\frac{1}{x-1}\ dx\Rightarrow\left|\begin{array}{ccc}x-1=t\\dx=dt\end{array}\right|\Rightarrow\int\frac{1}{t}\ dt=lnt+C_1=ln(x-1)+C_1

\#2\ \int\frac{x}{x^2+9}\ dx\Rightarrow  \left|\begin{array}{ccc}x^2+9=u\\2x\ dx=du\\x\ dx=\frac{1}{2}\ du\end{array}\right|\Rightarrow\int\left(\frac{1}{2}\cdot\frac{1}{u}\right)\ du=\frac{1}{2}\int\frac{1}{u}\ du\\\\\\=\frac{1}{2}ln(u)+C_2=\frac{1}{2}ln(x^2+9)+C_2

\#3\ \int\frac{1}{x^2+9}\ dx=\int\frac{1}{x^2+3^2}\ dx=\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3\\\\therefore:\\\\\#1;\ \#2;\ \#3\Rightarrow(**)=ln(x-1)+C_1-\frac{1}{2}ln(x^2+9)+C_2-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C_3

\boxed{=ln(x-1)-\frac{1}{2}ln(x^2+9)-\frac{1}{3}tan^{-1}\left(\frac{x}{3}\right)+C}



4 0
3 years ago
Susie sent out party invitations to 8 people from each of her three activity clubs. How many people did she invite to her party?
IrinaK [193]

Invito a 24 personas

8X3=24

6 0
2 years ago
Please help me I'm confused on this.
abruzzese [7]

Answer:

divide by 8

2.25 cubic units

Step-by-step explanation:

3 x 6 half cubes = 18 half cubes

one cubic unit =1/8 cubic units

18/8=2.25 cubic units

7 0
2 years ago
Read 2 more answers
Your family buys tickets for the Ranger game. Each ticket costs $16. You also have to pay for parking. After buying 4 tickets, y
Yuliya22 [10]

Part (a)

Answer: $32.50

--------------------

Work Shown:

Each ticket costs $16. If you buy four of them, then you paid 4*16 = 64 dollars.

The total bill was $96.50

This leaves 96.50-64 = 32.50 for parking.

======================================================

Part (b)

Answer:  y = 16x+32.50

--------------------

Work Shown:

x = number of tickets

y = total bill (in dollars)

1 ticket costs 16 dollars

x tickets cost 16x dollars since we multiply both values by x

Add on the cost of parking to get a total bill of y = 16x+32.50

======================================================

Part (c)

Answer:  at most 13 tickets

In other words, 13 is the max you can get.

--------------------

Work Shown:

Plug y = 250 into the equation found back in part (b). Solve for x

We'll follow PEMDAS in reverse to isolate x

y = 16x+32.50

250 = 16x+32.50

16x+32.50 = 250

16x = 250-32.50

16x = 217.5

x = 217.5/16

x = 13.59375

Since we can't buy a fraction of a ticket, we must round down to the nearest whole number. We cannot round to x = 14 despite the value 13.59375 being closer to 14 as it is to 13.

x = 13 is the answer we're after.

If we plug in x = 13, we get

y = 16x+32.50 = 16*13+32.50 = 240.5

while x = 14 leads to

y = 16x+32.50 = 16*14+32.50 = 256.5

The first result of $240.50 is under $250 while the second result $256.50 is over $250. So that's why x = 13 is the largest number of tickets we can buy.

6 0
2 years ago
Can someone help me with this geometric models questions?
kolbaska11 [484]
Answer: Jen’s 83
Step by step;
6 0
3 years ago
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