It can't be a whole number. It can be 1.5, or 1 1/2.
Add the x and y and you will get 4x^4=8y^2
Answer:
a) Observe that
![G=\left[\begin{array}{ccc}2&6\\4&0\end{array}\right] =2\left[\begin{array}{ccc}1&3\\2&0\end{array}\right] =2F](https://tex.z-dn.net/?f=G%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%266%5C%5C4%260%5Cend%7Barray%7D%5Cright%5D%20%3D2%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%5C%5C2%260%5Cend%7Barray%7D%5Cright%5D%20%3D2F)
Then, 
b) The zero matrix satisfies that for every matrix B such that the product is well defined, 
Since the matrix G is the zero matrix then 
c) The identity(Id) matrix satisfies that for that for every matrix B such that the product is well defined Id*B=B=B*Id. Observe that G is the identity matrix, then FG=F*Id=F=Id*F=GF
d) Observe that
![G=\left[\begin{array}{ccc}3&0&0\\0&3&0\\0&0&3\end{array}\right] =3\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] =3Id](https://tex.z-dn.net/?f=G%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%260%260%5C%5C0%263%260%5C%5C0%260%263%5Cend%7Barray%7D%5Cright%5D%20%3D3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%3D3Id)
.
Then 
Answer: it will take 17.33 years to double.
Step-by-step explanation:
The formula for continuously compounded interest is
A = P x e^(r x t)
Where
A represents the future value of the investment after t years.
P represents the present value or initial amount invested
r represents the interest rate
t represents the time in years for which the investment was made.
e is the mathematical constant approximated as 2.7183.
From the information given,
P = 425
A = 2 × 425 = 850
r = 4% = 4/100 = 0.04
Therefore,
850 = 425 x 2.7183^(0.04 x t)
850/425 = 2.7183^(0.04t)
2 = 2.7183^(0.04t)
Taking ln of both sides, it becomes
Ln 2 = 0.04t ln 2.7183
0.693 = 0.04t
t = 0.693/0.04
t = 17.325
Answer:
SA: 231
Step-by-step explanation:
8(12) + 2(5(12)) + 5(3)
96 + 120 + 15 = 231
I hopoe I helped you ;)
