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3 years ago

What is the length of DE

Mathematics

1 answer:

HACTEHA [7]3 years ago

8 0

Answer:

DE = 20units

Step-by-step explanation:

In Δ ABC,

angle A is congruent to angle B.... (given)

therefore, ΔABC is an isoceles triangle.

therefore, CA = CB..... (side opposite to congruent angles are congruent in an isoceles triangle)

therefore, CB = 4 units

In ΔCDE,

angle D is congruent to angle E.... (given)

therefore, ΔCDE is an isoceles triangle.

therefore, CD = CE

therefore, CD = 8 units

ΔCDE ~ ΔCBA

therefore,

$\frac{cd}{cb} = \frac{ce}{ca} = \frac{de}{ab} \\ therefore \: \frac{8}{4} = \frac{8}{4} = \frac{de}{10 } \\ therefore \\ \frac{2}{1 } = \frac{de}{10 } \\ de \: = 2 \times 10 = 20units$

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A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

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Then

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$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

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Ummmm i believe your answer is A. just divide next time :)

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Marianna [84]

Answer:

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Step-by-step explanation:

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becomes

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3 years ago

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gayaneshka [121]

Answer:

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Answer:

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Since she had 20 dollars remaining from may, she earned the rest of the money in june so:

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