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yan [13]
2 years ago
13

What is pseudocode? O A way of describing a set of instructions in text form using plain english O A diagrammatic representation

of a set of instructions O A specific programming language that all computers use O a markup language​
Computers and Technology
1 answer:
Marat540 [252]2 years ago
8 0

The definition of pseudocode is that; A: A way of describing a set of instructions in text form using plain English

<h3>What is Pseudocode? </h3>

In computer science, pseudocode is defined as a plain language description of the steps in an algorithm or another system.

Now, the way Pseudocode works is that it often makes use of structural conventions of a normal programming language to be utilized for human reading instead of machine reading.

Pseudocode usually omits details that are essential for machine understanding of the algorithm, such as variable declarations and language-specific code.

Read more about Pseudocode at; brainly.com/question/11623795

You might be interested in
Write a program that reads the balance and annual percentage interest rate and displays the interest for the next month. Python
denis23 [38]

Answer:

Explanation:

The following code is written in Python. It asks the user to enter the current balance and the annual interest rate. It then calculates the monthly interest rate and uses that to detect the interest that will be earned for the next month. Finally, printing that to the screen. A test output can be seen in the attached picture below.

balance = int(input("Enter current Balance: "))

interest = int(input("Enter current annual interest %: "))

interest = (interest / 12) / 100

next_month_interest = balance * interest

print('$ ' + str(next_month_interest))

7 0
3 years ago
The ______ clause allows us to select only those rows in the result relation of the ____ clause that satisfy a specified predica
baherus [9]

Answer:

1. Where,

2. From

Explanation:

In SQL query language when working on a database, a user can use certain clauses to carry out some functions.

Hence, The WHERE clause allows us to select only those rows in the result relation of the FROM clause that satisfy a specified predicate.

This is because the "Where clause" selects the rows on a particular condition. While the "From clause" gives the relation which involves the operation.

5 0
3 years ago
Adding videos to your website can be tricky because there may be problems making sure they will play in all
Volgvan
The sentence ends with the word 'devices'
4 0
3 years ago
The way a particular application views the data from the database that the application uses is a.
masha68 [24]

The way a particular application views the data from the database that the application uses is a sub-schema.

<h3>What is Database?</h3>

A Database may be defined as a process of collecting data and information that is principally assembled for quick search and recoupment by a computer.

The sub-schema is the reasoning elucidation of that section of the database which is applicable and accessible to a specific application. This type of database is common to two or more applications.

Therefore, the sub-schema is the way through which a particular application views the data from the database that the application uses.

To learn more about Database, refer to the link:

brainly.com/question/26096799

#SPJ4

4 0
2 years ago
Question is attached as image, please help :&gt;
harkovskaia [24]

Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

3 0
3 years ago
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