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DaniilM [7]
2 years ago
8

Help pls pls pls pls pls pls pls

Mathematics
1 answer:
sergiy2304 [10]2 years ago
8 0

Answer:

485

Step-by-step explanation:

Q(-9) = 6(-9)² - 1 = 6×81 - 1 = 486 - 1 = 485

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Evaluating expressions
Dvinal [7]

Answer:

There is no expression to evaluate.

Step-by-step explanation:

5 0
3 years ago
Tables do not include numerical data. True or false?
stepan [7]
True all table does not need to include numerical data 
5 0
3 years ago
Read 2 more answers
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
According to this diagram, what is cos 28°? 62° 17 8 28° 90° 15 O A. 17 15 O B. 8 17 O c. 15 17 O D. O E. 8 15 15 OF.​
VikaD [51]

Answer:

C. Cos(28) = \frac{15}{17}

Step-by-step explanation:

Recall: SOHCAHTOA

Thus,

Cos(\theta) = \frac{Adjacent}{Hypotenuse}

Reference angle = 28°

Adjacent = 15

Hypotenuse = 17

Plug in the values

Cos(28) = \frac{15}{17}

4 0
3 years ago
I got 10 but can someone make sure because I want to get a 100
Sati [7]

Answer:

i think 10

Step-by-step explanation:

6 0
3 years ago
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