Answer: you need a x and y axis to get this answer
Step-by-step explanation: first you put the (3,5) and (3,-7) in a graph paper then make an y and x axis and you will be able to see your answer visually
Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
<h3>How to Apply the Linear Pair Theorem?</h3>
Given the following angles in the image above:
Measure angle RSU = (17x - 3)°,
Measure angle UST = (6x – 1)°
To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:
m∠RSU + m∠UST = 180 degrees (linear pair]
Substitute the values
17x - 3 + 6x - 1 = 180
Solve for x
23x - 4 = 180
23x = 180 + 4
23x = 184
x = 8
m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]
m∠TSV = 180 - 2(6x - 1)
Plug in the value of x
m∠TSV = 180 - 2(6(8) - 1)
m∠TSV = 86°
Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
Learn more about the linear pair theorem on:
brainly.com/question/5598970
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Answer:
C
Step-by-step explanation:
Use πr²
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
