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hoa [83]
3 years ago
9

PLEASE HELP!!! will give brainlisest

Mathematics
2 answers:
nikklg [1K]3 years ago
3 0

Answer:

\sf \dfrac{x}{8}-22

Explanation:

\rightarrow \sf \left(\dfrac{7}{8}x-4\right)-3\left(\dfrac{1}{4}x+6\right)

<u>remove parenthesis</u>

\sf \rightarrow \dfrac{7}{8}x-4-\dfrac{3x}{4}-18

<u>expand</u>

\rightarrow \sf \dfrac{7x}{8}-\dfrac{3x}{4}-22

<u>simplify</u>

\rightarrow \sf \dfrac{x}{8}-22

Snowcat [4.5K]3 years ago
3 0

Answer:

\frac18x-22

Step-by-step explanation:

Given expression:

(\frac78x-4)-3(\frac14x+6)

Expand:

\implies \frac78x-4-\frac34x-18

Gather like terms:

\implies \frac78x-\frac34x-4-18

Change 3/4 into eighths:

\implies \frac78x-\frac68x-4-18

Combine like terms:

\implies \frac18x-22

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A block of copper weighs 2160g and has a volume of 240cm3. what is the density of the copper?
densk [106]
The unit of density [kgm^-3] displays the formula.
So density=mass/volume.

Convert 2160g into kilograms [2160/1000=2.160kg]
Convert volume of 240cm^3 into m^3
100cm=1m
100x100x100=1000000cm^3=1m^3
240/1000000=[2.4x10^-4]

Final calculation
2.160/2.4x10^-4=9000

Answer: 9000kgm^-3
3 0
3 years ago
Andrew has an equal positive number of quarters, dimes, and nickels in his bag. The total amount of money Andrew has in his bag
kvasek [131]

Answer:

  $2

Step-by-step explanation:

One group consisting of one of each of the coins has a value of $0.40. The least common multiple of $0.40 and $1.00 is $2.00.

___

In cents, ...

  40 = 2^3 · 5

  100 = 2^2 · 5^2

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4 0
4 years ago
What is the value of x, given that PQ parallel to BC
scoundrel [369]

Answer:

since PQ ||BC,

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8 0
3 years ago
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What is 13/100 in simplest form?
Kipish [7]
It's already in simplest form, 13 is a prime number
4 0
3 years ago
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What is the product? StartFraction 2 y Over y minus 3 EndFraction divided by StartFraction 4 y minus 12 Over 2 y + 6 EndFraction
Naddika [18.5K]

Answer:

(y^2 + 3y) / (y^2 - 6y + 9)

Factored form: [y*(y+3)] / [(y-3)^2]

Step-by-step explanation:

We need to find the following product:

(2y / y-3) / ((4y-12) / (2y+6))

We have a division of fractions. We can transform this in a product, where we have the first fraction multiplied by the inverse of the second fraction. So, we have that:

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= 2y*(2y+6) / ((y-3)*(4y-12))

= [2y * 2 * (y+3)] / [4 * (y-3) * (y-3)]

= [y*(y+3)] / [(y-3) * (y-3)]

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