This isn't really a geometry problem. It's just an addition of fractions.
You know that 'perimeter' means 'the distance all the way around'.
And you know the length of all the sides of the parallelogram.
All you need to do is add them up !
(13/12) + (3/13) + (13/12) + (3/13) = the perimeter
Notice that two of the sides are equal, and the other two sides are also equal.
So you can make the job a little easier if you add up the twelfths first
(13/12) + (13/12) = 26/12
and then add up the thirteenths ...
(3/13) + (3/13) = 6/13 .
Now, the perimeter looks a little bit less complicated.
It's just
(26/12) + (6/13) = the perimeter.
This is the tough part. Before you can add fractions, they need to have
a common denominator.
The smallest common denominator for 12ths and 13ths is <em>156 </em>!
Change each fraction to (<em>something over 156</em>), and add um up.
I'll leave that part to you.
Your answer is the first option, 8.0. You can find this by using the sine rules for sides, so:
10/sin(90) = x/sin(53)
× sin(53)
7.98 = x
And 7.98 rounded to the nearest tenth is 8.0.
I hope this helps!
Answer:
3-n=14
Step-by-step explanation less than a number!!! If a number is unkown it would be a variable, a letter,
Answer:
- 1 5/24 cm
Step-by-step explanation:
We'll have to get the fractions to a common denominator. the least common denominator for 3 and 80 is 240.
So - 1 1/3 = - 1 80/240 = 320/240
21/80 = 63/240
-11/80 = -33/240
-------------------------------------
-320/240 + 63/240 - 33/240 = -290/240 = - 1 50/240 = -1 5/24 cm
