Given,
SP~QP
SR~QR
In ∆SRP and ∆QRP
SP~QP (given)
SR~QR (given)
PR=PR (common)
Therefore,
∆SRP~∆QRP by SSS congruence rule.
The answer is A.
y = x^2 + 2 simply means that y is whatever x is to the second power, plus 2. so, -2^2 = 4. 4 + 2 = 6.
you can work this through the other options but A is the answer.