Answer:
function dataSamples=AdjustMinValue(numberSamples, userSamples, minValue)
dataSamples=userSamples;
%for loop
for i=1:numberSamples
%checking if dataSamples value at index,i
%is less than minValue
if dataSamples(i)<minValue
%set double of dataSamples value
dataSamples(i)= 2*dataSamples(i);
end
end
end
Explanation:
The given code is in MATLAB.
Answer:
void print2(int row) {
for (int i = 0; i < row; i++) {
char ch = 'a';
char print = ch;
for (int j = 0; j <= i; j++) {
cout << print++;
}
cout << endl;
}
}
int count_digits(int num) {
int count = 0;
int temp = num;
while (temp != 0) {
temp = temp / 10;
count++;
}
return (num % count);
}
Explanation:
Answer:
Programmers can take advantage of abstraction to focus on specific tasks.
Explanation:
When we excel in some subjects, we can do abstraction in that subject. Abstraction means you understand by the term, and you do not need details of that term. Like you say some tasks will be done by a graphic designer as a project manager, and you do not need to understand at that point what he will be doing, and that is because you can write in a word or few what is going to be the outcome. And hence, the programmers can take advantage of abstraction to focus on specific tasks. And this is the correct option.
Answer:
For question a, it simplifies. If you re-express it in boolean algebra, you get:
(a + b) + (!a + b)
= a + !a + b
= b
So you can simplify that circuit to just:
x = 1 if b = 1
(edit: or rather, x = b)
For question b, let's try it:
(!a!b)(!b + c)
= !a!b + !a!bc
= !a!b(1 + c)
= !a!b
So that one can be simplified to
a = 0 and b = 0
I have no good means of drawing them here, but hopefully the simplification helped!
