Answer:
Unit testing is the software testing method in which the individual source code are associate to control data. Unit testing basically test the code to ensure that the data or information meets its design.
The aim of unit testing that each part isolate in the program and display the correct individual parts.
Unit testing tool are efficient as they provide several benefits in the development cycle. The basic efficiency of unit testing tools depend upon its type of testing. Unit testing basically validate the units of source code in the program.
For example: when the loop and function in the program work efficiently.
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Complete Question: You decide to bulk upload your multiple business locations to Google My Business. Some of the locations in your upload were disapproved. Which two errors can cause this issue? (Choose two.)
A Missing listing photos
B Late listing registration
C Multiple locations in one physical address
D Too many listing users
E Incorrect business name
Answer:
C) Multiple locations in one physical address
E) Incorrect business name
Explanation:
Google provides a service called Google My Business which allows users with the aid of special tools create, update and maintain their business profiles on the internet. In this way, users are able to build free simple websites and publish posts to engage their customers more effectively.
In the process of signing up for this service, new users are required to verify their business names and physical locations, In the given question a user trying to upload multiple business locations will not get approval if he uploads Multiple locations in one physical address or enters an Incorrect business name.
