Casey is selling adult tickets and student tickets for the school play. The adult tickets cost $6.00 and the student tickets cos
t $4.00. Casey sells 120 tickets and makes $560.00. Which system of equations could be used to find the cost of each ticket?
1 answer:
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Answer:
Nearly 83 students did not had activity card.
Nearly 42 students had an activity card.
Step-by-step explanation:
Total number of tickets sold at homecoming = 125
Cost of each ticket without activity card = $20.5
Cost of each ticket with activity card = $15.75
Total amount earned = $2365
Let, the number of tickets sold without activity car d = k
So, the number of tickets sold without card = (Total sold - k)
= 125 - k
Now, according to the question:
$20.5(k) + $15.75(125 - k) = $2365
or, 20.5 k + 1968.5 - 15.75 k = 2365
⇒ 4.75 k = 2365 - 1968.5 = 396.5
⇒
Hence, nearly 83 students did not had activity card.
So,the number of students that had activity card = 125 - 83.47 = 41.53 ~ 42
Hence, nearly 42 students had an activity card.