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Anuta_ua [19.1K]
3 years ago
7

One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 500,

find the numbers
Mathematics
1 answer:
Likurg_2 [28]3 years ago
8 0
<span>Let the first number be x.
Then the second number is 3x.
Then the third number is (x+100).
Sum of the numbers=500

x+3x+(x+100)=500</span>
<span>4x+(x+100)-500=0
</span><span>5x=400</span>
<span>x=80
</span><span>The first number is 80.
The second number is 240.
The third number is 180.

We can check by adding all three of those numbers together: 80+240+180 = 500
</span>
Hope this helps! If you have any questions just ask!
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Complete Question:

Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.

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Given

A: (4x^2 - 4x)(x^2 - 4)

B: (x^2 + x - 2)(4x^2 - 8x)

Required

Determine how they can show if the products are the same or not

To do this, we simply factorize each polynomial

For, Polynomial A: We have:

A: (4x^2 - 4x)(x^2 - 4)

Factor out 4x

A: 4x(x - 1)(x^2 - 4)

Apply difference of two squares on x^2 - 4

A: 4x(x - 1)(x - 2)(x+2)

For, Polynomial B: We have:

B: (x^2 + x - 2)(4x^2 - 8x)

Expand x^2 + x - 2

B:(x^2 + 2x - x - 2)(4x^2- 8x)

Factorize:

B:(x(x + 2) -1(x + 2))(4x^2- 8x)

Factor out x + 2

B:(x -1) (x + 2)(4x^2- 8x)

Factor out 4x

B:(x -1) (x + 2)4x(x- 2)

Rearrange

B: 4x(x - 1)(x - 2)(x+2)

The simplified expressions are:

A: 4x(x - 1)(x - 2)(x+2) and  

B: 4x(x - 1)(x - 2)(x+2)

Hence, both polynomials are equal

A = B

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