I like to start by turning all my numbers into the same form. You can go either way but I am going to turn the decimals into fractions. so 0.7 is the same as 7/10.
0.755 is like 755/1000 which can be reduced to 151/200 (if you don't understand the convertions let me know i will explaine more.)
Next give all the fractions a common denominator. both 8 and 10 go into 200 so we can use that. 151/200 already has a denominator of 200 so that one is set.
for 7/10 well, 10 time 20 is 200 so multiply both the numerator and the denominator by 20 so you get 140/200
the last one is 5/8 8 times 25 is 200 so multiply both numbers by 25 to get 125/200
the fractionos we have are 125/200 151/200 and 140/200. Now because they all have the same denominator the one with the lowest numerator is the least number and the one with the highest number is the greatest number.
125/200 140/200 151/200 now just replace the original number with the order they are placed in.
125/200 was 5/8
140/200 was 0.7
151/200 was 0.755
so the final answer is
5/8, 0.7, 0.755
Answer:
11 pies
Step-by-step explanation:
100-12=88
88/8=11
Answer:
2x+20 + x+40 = 180
Step-by-step explanation:
The angles are supplementary so they add to 180
2x+20 + x+40 = 180
Answer:
It is a many-to-one relation
Step-by-step explanation:
Given
See attachment for relation
Required
What type of function is it?
The relation can be represented as:
![\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy%5C%5C%20%5C%5C10%5C%5C11%5C%5C4%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Where
and 
Notice that the range has an occurrence of 10 (twice)
i.e.
and 
In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>