Answer:
720
Step-by-step explanation:
nPk = n!/(n-k)!
10P3 = 10!/(10-3)! = 10!/7!
= 10·9·8 = 720
![x^ \frac{m}{n}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7Bm%7D%7Bn%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
pemdas, so exponent first before multiply
4(x^1/2)=4x^2
this is different from
(4x)^1/2
so
![x^ \frac{1}{2}= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%20%5Cfrac%7B1%7D%7B2%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20%20)
times that by 4
4√x
Public schools are free to use for the public (despite uniform and others), and jobs involved in public schools (like teachers) get their money from the government as everything funded towards public schools are by the government
the answer is
x=8y/3(1-8y)
y=3x/8(1+3x)
hope this helped l used cymath to solve this problem.
good day : )
Answer: See explanation
Step-by-step explanation:
Your question isn't complete but let me give different scenarios to help you solve.
Firstly, assuming we want to calculate the amount of items left after the large items are carried alone, this will be:
= 561 - 36
= 525
Secondly, if we want to know the percentage of the large items that will be carried alone. This will be:
= 36/561 × 100.
= 6.42%
Thirdly, if you want to know the percentage of the items that will be left after the large ones have been carried alone. This will be:
= 100% - 6.42%
= 93.58%
