Answer:
We can see that both the triangles are congruent to each other.
So, PQ = TU (CPCT), Thus TU = <u>6</u><u>0</u><u>.</u>
Consider the triangles formed by the lines of sight in parts a and b. In part a, the distance from the horizontal to the base of the antenna is 82.0*tan31.0º; in part b, the distance from the horizontal to the top is 82.0*tan34.2º. The antenna height is the difference between these
<span>h = 82.0*tan34.2º - 82.0*tan31.0º = 82.0*(tan34.2º - tan31.0º) = 6.46 m</span>
X=5
90°-50°=40°
5x+15=40°
5x=25°
x=5