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ad-work [718]
2 years ago
15

CAN SOMEONE PLS HELP ME WITH THIS? ITS SO URGENT (Pls show solution too)

Mathematics
1 answer:
FinnZ [79.3K]2 years ago
4 0

Answer:

Step-by-step explanation:

t + u = 11 ----------- (1 )

10t + u = 10u + t - 9

10t + u - 10u - t = -9

10t - t + u - 10u = - 9

Combine like terms

9t - 9u = -9

Divide the entire equation by 9

\dfrac{9}{9}t-\dfrac{9}{9}u=\dfrac{-9}{9}

t - u = -1  --------------(2)

Add equation (1) & (2) and so, u will be eliminated and we can find the value of t

(1)       t + u = 11

(2)      <u>t  - u = -1</u>

         2t     = 10

               t = 10/2

t = 5

Plugin t = 5 in equation (1)

5 + u = 11

    u = 11 - 5

u = 6

The original number is 56

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Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
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Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
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6 11/24

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James reads that 1 out of 6 eggs contains salmonella bacteria. So he never uses more than 5 eggs in cooking. If eggs do or don't
Dmitrij [34]

Answer:

B. binomial with n = 5 and p = 1/6

Step-by-step explanation:

Given that James reads that 1 out of 6 eggs contains salmonella bacteria.

So he never uses more than 5 eggs in cooking.

If eggs do or don't contain salmonella independently of each other, then

probability for any one egg to contain salmonella bacteria is the constant 1/6.

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3 0
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