Answer/Step-by-step explanation:
1. Side CD and side DG meet at endpoint D to form <4. Therefore, the sides of <4 are:
Side CD and side DG.
2. Vertex of <2 is the endpoint at which two sides meet to form <2.
Vertex of <2 is D.
3. Another name for <3 is <EDG
4. <5 is less than 90°. Therefore, <5 can be classified as an acute angle.
5. <CDE is less than 180° but greater than 90°. Therefore, <CDE is classified as an obtuse angle.
6. m<5 = 42°
m<1 = 117°
m<CDF = ?
m<5 + m<1 = m<CDF (angle addition postulate)
42° + 117° = m<CDF (Substitution)
159° = m<CDF
m<CDF = 159°
7. m<3 = 73°
m<FDE = ?
m<FDG = right angle = 90°
m<3 + m<FDE = m<FDG (Angle addition postulate)
73° + m<FDE = 90° (Substitution)
73° + m<FDE - 73° = 90° - 73°
m<FDE = 17°
G because the first jelly bean was put back so it doesn't matter.
Answer:
Part A. C=9
Part B. (w+3)² =139
Part C. w = 8.8 inch
Step-by-step explanation:
Given from the question length of the the picture = (2w+12) inches
Width of the picture = w inches
Area of the picture = 260 inch²
Part A. Area of the picture with the given dimensions= w×(2w+12)
Or w(2w+12) = 260
2w²+12w = 260
2(w²+6w) = 2×(130)
w²+6w = 130
Or w²+6w +9 = 130+9 ⇒ which is in the form of w²+6w+c = 130+c
Therefore for c = 9 we will get a perfect square trinomial.
Part B. As we have seen the equation in part A.
As required equation will be (w+3)²=139
Part C. Since (w+3)² = 139
Then by taking under root on both the sides of the equation
(w+3) =√139 = 11.8
(w+3)-3=11.8-3
w = 8.8 inch
The number of gallons of water in the tank at t=10 is
... W(10) = 160,000 -10(8000 -10) = 80100
The number of gallons of water in the tank at t=10.5 is
... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25
The rate of change over the interval is
... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5
The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.
The sign is negative, so the amount of water is decreasing.
If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
