12.568% is the correct answer
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer: A
Step-by-step explanation: this is the only answer because the other two solutions are
A: 4>3 correct
B: 3>3 wrong
C: 2>3 wrong
Answer:
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
Step-by-step explanation:
1. Let's check all the information provided to answer the question:
Time of Thomas flight delay = 1 5/6 hours
Time of normal flight = x hours
2. How long did the trip finally take?
For calculating how long the trip finally took, we need to do the following sum:
Time of normal flight + Time of delay
Like we don't know the time of the normal flight, we will define it as x, then:
x + 1 5/6 hours
x + 1 hour and 50 minutes ⇒ 5/6 of an hour = 5/6 * 60 minutes = 50 minutes
<u>Finally, the trip of Thomas will take an hour and fifty minutes more than the normal time it usually takes.</u>
Answer: D: 4x+3y=-6
Step-by-step explanation:
