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Lilit [14]
3 years ago
9

The relative atomic mass of aluminium is 27 and of oxygen is 16. The aluminium ore shown below contains 5. 4kg of aluminium and

4. 8kg of oxygen. What is the value of x?
SAT
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:Hope this helps :D

Explanation:

Cu = 27, S = 16 and O = 25.92

relative formula mass = 27 + 16 + (5.4x4.8) = 286.216

only one aluminum atom of relative atomic mass

64 % Cu = 100 x 64 / 160

x = 1036.8

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b) Find the t-value such that the area in the right tail is 0.01 with 11 degrees of freedom

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QUESTION 1
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In a certain isosceles triangle, the base is $1\frac 12$ times as long as each leg and the perimeter is $63. $ how long is the b
V125BC [204]

The length of the base of the isosceles triangle is: 27 units long.

<h3>What is an isosceles Triangle?</h3>

A triangle with two equal legs and a base is called an isosceles triangle.

Thus:

Let x represent the length of each of the equal legs of the isosceles triangle.

Therefore:

The length of the base = 1 1/2(x) = 1.5x units

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Therefore:

x + x + 1.5x = 63

3.5x = 63

x = 63/3.5

x = 18

The length of the base = 1.5x units

Plug in the value of x

The length of the base = 1.5(18) = 27 units

Therefore, the length of the base of the isosceles triangle is: 27 units long.

Learn more about isosceles triangle on:

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2 years ago
How many times can you say something be for it is a tongue twister message me and let me know
Troyanec [42]
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5 0
3 years ago
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A 0.1 kg block of brass is cooled until it releases 56.4 J of heat. If the temperature of the block was 5 K initially, what is i
Zolol [24]

Answer:

3.5 K

Explanation:

When a sample of a substance releases heat energy, its temperature decreases according to the equation:

Q=mC(T_f-T_i)

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Q is the heat energy released

m is the mass of the substance

C is the specific heat capacity

T_i is the initial temperature

T_f is the final temperature

For the block of brass in this problem, we have:

m = 0.1 kg is the mass

Q = -56.4 J is the heat energy released (negative since it is released)

C = 380 J/kg K is the specific heat capacity of brass

T_i=5 K is the initial temperature

Solving for T_f, we find the final temperature:

T_f=T_i + \frac{Q}{mC}=5+\frac{-56.4}{(0.1)(380)}=3.5 K

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3 years ago
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