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2 years ago

Employment Frequency

Mathematics

1 answer:

Citrus2011 [14]2 years ago

5 0

Answer:

my appleas arw yellow

Step-by-step explanation:

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(2h3 + 6h) + (3h3 - 7h - 3) standard form sum or difference.

worty [1.4K]

Answer:

$5h^3- h - 3$

Step-by-step explanation:

Given

$(2h^3 + 6h) + (3h^3 - 7h - 3)$

Required

Standard form

We have:

$(2h^3 + 6h) + (3h^3 - 7h - 3)$

Remove bracket

$(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 6h + 3h^3 - 7h - 3$

Collect like terms

$(2h^3 + 6h) + (3h^3 - 7h - 3) =2h^3 + 3h^3+ 6h - 7h - 3$

$(2h^3 + 6h) + (3h^3 - 7h - 3) = 5h^3- h - 3$

Hence, the standard form is:

$5h^3- h - 3$

3 0

3 years ago

Ten less than the quotient of a number and 3 is 8

sashaice [31]

Answer:

Step-by-step explanation:

x-10+3=8

x-7=8

x=15

4 0

3 years ago

6x^3-16x^2+17x-6?/3x-2

liraira [26]

Answer:

2x² − 4x + 3

Step-by-step explanation:

x = 2/3 is a root of both the numerator and the denominator, so it divides evenly. Therefore, one method is to factor by grouping:

6x³ − 16x² + 17x − 6

6x³ − 4x² − 12x² + 17x − 6

2x² (3x − 2) − (12x² − 17x + 6)

2x² (3x − 2) − (4x − 3) (3x − 2)

Divided by 3x − 2:

2x² − (4x − 3)

2x² − 4x + 3

Another method is to use long division (see image).

4 0

4 years ago

creativ13 [48]

If the diameter is 12 inches, the radius is 6 inches, because the radius is half the diameter.

Given the formula

$A=\pi r^2$

we have

$A=36\pi$

When you fold the circle in half, the resulting figure has half the area.

So, you start with a circle with area $36\pi$

You fold it once and you have a semicircle with area $18\pi$

You fold it twice and you have a quarter circle with area $9\pi$

7 0

3 years ago

Simplify (3x)-1. A. 81x^4. B. 4x^6. C. 1/3x. D. 1/x^6

elena55 [62]

If you mean: (3x)^-1

When you have a power to a negative number (1 in this case), place the power on the numerator, with the base in the denominator.

(3x)^-1 = 1/3x

1/3x, or C) is your answer

hope this helps

3 0

3 years ago