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Simora [160]
3 years ago
9

Carey creates the table below to help him determine 75% of 36.

Mathematics
1 answer:
Setler [38]3 years ago
7 0

Answer:

27

Step-by-step explanation:

75×36=2700

2700/100=27

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At a gas station, it takes 14 seconds to pump 2 gallons of gas. if the amount of gasoline pumped varies directly with time, how
EleoNora [17]

Answer:

See below:

Step-by-step explanation:

If we do this, we know that 2 gallons takes 14 seconds. (2:14)

Based on that data, we can know that 1 gallon takes 7 seconds. (1:7)

-> 2/14 = 1/7

Now we can multiply by 12 to get 12 gallons on one side.

What we do on one side has to happen to the other side.

So, 12 gallons * 1 gallons = 12 gallons and 12 gallons * 7 gallons = 84 gallons.

So the final answer is 85 gallons,

7 0
3 years ago
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I need help with both questions...
NikAS [45]

Answer:

17. a)

Step-by-step explanation:

17.

f(x) =x/2, then f(x-3)=(x-3)/2

x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)

f(x-3)+3=0+3=3

18.

f(x) =x/2

f(x-2) for x=5 is f(5-2)=f(3)=3/2

f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2

3 0
3 years ago
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Triangle angle- sum theorem <br>help!!!<br>​
PIT_PIT [208]

Answer:

222555413`125431534

Step-by-step explanation:

8 0
3 years ago
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Is 73 a prime number
lora16 [44]
Hi there, 

73 indeed a prime number 

A prime number<span> (or a </span>prime) is a natural number<span> greater than 1 that has no positive divisors other than 1 and itself. A </span>natural number<span> greater than 1 that is not a </span>prime number<span> is called a composite </span><span>number!</span>
6 0
3 years ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
3 years ago
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