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kondaur [170]
3 years ago
13

Hello I need help on this math question​

Mathematics
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

153.9

Step-by-step explanation:

Diametre = 14, Radius = diametre/2 = 14/2 = 7

Area of circle = π*r^2,   π=3.14

= 3.14*7^2

=3.14*49

=153.9

Thepotemich [5.8K]3 years ago
3 0
I think it is either a b or c
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Answer: The value of g(x) is x+3.

Step-by-step explanation:

Since we have given that

h(x)=f\circ g(x)

Here,

h(x)=\sqrt{x+5}\\\\and\\\\f(x)=\sqrt{x+2}

We need to find the value of g(x):

f(x)=\sqrt{x+2}\\\\f(g(x))=\sqrt{g(x)+2}\\\\h(x)=\sqrt{g(x)+2}\\\\\sqrt{x+5}=\sqrt{g(x)+2}\\\\x+5=g(x)+2\\\\g(x)=x+5-2=x+3

Hence, the value of g(x) is x+3.

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Determine whether 81a2 − 25z6 is a difference of two squares. If so, factor it. If not, explain why.
aev [14]

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Step-by-step explanation:

The difference of two squares is a binomial of two terms each term is a square and the sign between the two terms is (-), its factorization is the product of two identical binomials with different middle signs

  • a² - b² is a difference of two squares
  • a² - b² = (a + b)(a - b)

∵ The binomial is 81 a² - 25 z^{6}

∵ \sqrt{81} = 9

∵ \sqrt{a^{2} } = a

∴ \sqrt{81a^{2}}=9a

∵ \sqrt{25} = 5

∵ \sqrt{z^{6}} = z³

∴ \sqrt{25z^{6}}=5z^{3}

- The two terms have square root

∵ The sign between them is (-)

∴ 81 a² - 25 z^{6}  is a difference of two squares

∵ Its factorization is two identical brackets with different

   middle signs

∵ 81 a² = 9a × 9a

∵ 25 z^{6} = 5z³ × 5z³

- The terms of the two brackets are 9a and 5z³

∴ 81 a² - 25 z^{6} = (9a + 5z³)(9a - 5z³)

81 a² - 25 z^{6} is a difference of two squares and its factors are (9a + 5z³) and (9a - 5z³)

Learn more:

You can learn more about the difference of two squares in brainly.com/question/1414397

#LearnwithBrainly

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3 years ago
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