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3 years ago

If 4 coins are tossed simultaneously what is the probability of getting exactly 3 heads

Mathematics

1 answer:

Alexus [3.1K]3 years ago

6 0

No of outcomes =16
favourable outcome=4
probability of getting exactly 3 heads=0.25

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Solve the equation. Check the solution. 9-17x-5-4x=7

Shalnov [3]

Answer:

x = -1/7

Step-by-step explanation:

Solve for x

9-17x-5-4x=7

Combine like terms

-21x +4 = 7

Subtract 4 from each side

-21x-4+4 = 7-4

-21x = 3

Divide each side by -21

-21x/-21 = 3/-21

x = -1/7

Check

9 - 17(-1/7) -5 -4(-1/7) =7

9 + 17/7 -5 + 4/7 =7

4 +21/7 = 7

4+3 = 7

7=7

3 0

1 year ago

Subtract five from three times a number and the result is equal to the number plus five. find the number.

allsm [11]

3(x)-5=x+5
3x=-5+5+x
3x=x
0=x
because 3x=x is basically would make each part into 0 which would end up the same.

6 0

3 years ago

Need help on this question asap pleasee

slavikrds [6]

Answer:

4th option

Step-by-step explanation:

The chord- chord angle 67.5° is half the sum of the arcs intercepted by the angle and its vertical angle, that is

67.5 = $\frac{1}{2}$ (x + 90)

6 0

3 years ago

1 1/4 + ( 3 2/3 + 5 3/4)

Dmitrij [34]

Answer:

10.6

10+ 2/3

Step-by-step explanation:

6 0

3 years ago

One rectangle has a base of 12 inches and an altitude of 6 inches. The other has a base of 10 inches and an altitude of 5 inches

guajiro [1.7K]

Ratio of their bases = $$\frac{12}{10}$

Ratio of their altitudes = $$\frac{6}{5}$

Step-by-step explanation:

For first rectangle, it was given that

Base 1 = 12 inches

Altitude 1 = 6 inches

For the second rectangle, it was given that

Base 2 = 10 inches

Altitude 2 = 5 inches

Ratio of their bases is given by the ratio of the base of the first rectangle to the second one.

Ratio of their altitudes is given by the ratio of the altitude of the first rectangle to the altitude of the second rectangle.

Ratio of their bases = $$\frac{12}{10}$

Ratio of their altitudes = $$\frac{6}{5}$

7 0

2 years ago