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Mkey [24]
2 years ago
8

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

rence of cubes? Check all that apply. (x – 4)(x2 4x – 16) (x – 1)(x2 – x 1) (x – 1)(x2 x 1) (x 1)( x – 1) (x 4)(x2 – 4x 16) (x 4)(x2 4x 16).
Mathematics
1 answer:
valentina_108 [34]2 years ago
8 0

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

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Hey, I need help with questions 1 and 2, if anyone can help, please? thanks!
Eva8 [605]

The correct works are:

  • Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3.
  • \frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

Blue(s + h) = 2(s + h)^2 + 3

Evaluate the exponent

Blue(s + h) = 2(s^2 + 2sh + h^2) + 3

Expand the bracket

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

Evaluate the like terms

\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

brainly.com/question/13136492

4 0
2 years ago
Whats the answer PLS
Alexxx [7]

Answer:

48+23(6)½

Step-by-step explanation:

A = l × w

A =[(8-(6)^½) × (9+4(6)^½)]

A =8(9+4(6)^½) + [-(6)^½(9+4(6)^½]

A =(72 + 32(6)^½ - 9(6)^½ - 24)

A =(72 - 24 + 32(6)^½ - 9(6)^½)

A =(48 + 23(6)^½)

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7B8ux%5E%7B5%7D%20%7D%20%5Csqrt%7B2ux%7D" id="TexFormula1" title="\sqrt{8ux^{5} } \sqr
lozanna [386]

Answer:

4ux³

Step-by-step explanation:

√8ux⁵ √2ux

√8*2 u*u x⁵*x

√16u²x⁶

4ux³

3 0
2 years ago
What is a good calculator that will give you the points to linear inequality systems?
satela [25.4K]

Answer:

I would just recommend you using M A T H W A Y and paying for the measly little $9.99 for the step-by-step answers.

Step-by-step explanation:

Or desmos would work but I would highly recommend m a t h w a y

4 0
2 years ago
Question 7<br> Which is the quotient of 1/5 divided by 3??
blondinia [14]

Answer:

1/5 divided by 3 =1/15 because when dividing a fraction by a whole number, it is gonna end as a fraction so the answer is 1/15. All you do is just multiply the denominator times the whole number and you will get your answer. Have a nice day! If this helped then please mark as brainliest.

6 0
2 years ago
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