Given:
μ = 200 lb, the mean
σ = 25, the standard deviation
For the random variable x = 250 lb, the z-score is
z = (x-μ)/σ =(250 - 200)/25 = 2
From standard tables for the normal distribution, obtain
P(x < 250) = 0.977
Answer: 0.977
Step by step:
3 2 1
× 6 4
————————————-
+ 1 2 8 4
+ 1 9 2 6 0
————————————-
= 2 0 5 4 4
Answer:
70cm
Step-by-step explanation:
,
Since, both of the tank posses the same quantity of water then there volume is the same thing
For rectangular base
Volume= (Lenght × breadth × hheight)
If we substitute values
Lenght= 80 cm
Breadth= 70 cm
height= 45 cm
Volume= 80cm × 70cm × 45cm
Volume= 252000cm^3
For square base
Volume= (side)^2 × height
side =60cm.
But volume of square base= volume of
rectangular base
252000cm^3= 60^2 × height
Height= (252000cm^3)/(60^2 )
Height= 70 cm
Hence, the second tank is 70 cm deep
Answer:
(A)48
(B)volume of one of the small cubes is 1/64cm^3
c)3/4x1x1=3/4cm^3
Step-by-step explanation:
Note:xy means x times y and x(y) means the same thing
so
first we get rid of square root then
make the equation equal to zero becaues if
xy=0 then x or/and y=0
squareroot(y-1)+3=y
isolate the squareroot
subtrac 3 from boht sides
squareroot(y-1)=y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot(y-1))^2=(y-3)^2
(y-1)=(y-3)(y-3)
y-1=y^2-6y+9
subtrac y from both sides
-1=y^2-7y+9
add 1 to both sides
0=y^2-7y+10
find what two number multiply to make 10 and add to get -7
the answer is -2 and -5
0=(y-5)(y-2)
therfore
y-5=0
and/or
y-2=0
therefor
y=5 or/and 2 might work
let's try out 2
square root(2-1)+3=2
square root(1)+3=2
1+3=2
false
so 2 doesn't work
let's try 5
squareroot(5-1)+3=5
squareroot(4)+3=5
2+3=5
5=5
true
y=5
