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Natasha_Volkova [10]
3 years ago
14

What is an equation of the line that passed through (-8,2) and has slope -3/4

Mathematics
1 answer:
Vlad [161]3 years ago
3 0
-3/4 * -8 = 2
-3/4x-4

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The table represents a sample of ages and people and their shoes size.
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Two ways to solve -2(4x+3)=12x-6
olasank [31]

Answer:

\huge\boxed{x=0}

Step-by-step explanation:

-2(4x+3)=12x-6\qquad\text{divide both sides by (-2)}\\\\4x+3=-6x+3\qquad\text{subtract 3 from both sides}\\\\4x=-6x\qquad\text{add}\ 6x\ \text{to both sides}\\\\10x=0\qquad\text{divide both sides by 10}\\\\\boxed{x=0}\\\\=================================

-2(4x+3)=12x-6\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-2)(4x)+(-2)(3)=12x-6\\\\-8x-6=12x-6\qquad\text{add 6 to both sides}\\\\-8x=12x\qquad\text{subtract}\ 12x\ \text{from both sides}\\\\-20x=0\qquad\text{divide both sides by}\ (-20)\\\\\boxed{x=0}

4 0
4 years ago
Help: I am a number between 60 and 100. My ones digit is six less than my tens digit. I am a prime number.
Reptile [31]

Answer:

Let's name the digit:

x- ones digit

y - tens digit

we know that x=y-2.

Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).

So the possibilities with x=y-2:

64

75

86

97

Out of those 64 and 86 are even, so they can't be prime.

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so the correct answer is 97.

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
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(10 points)I REALLY NEED HELP NOW!! (A) positive (b)negative (c)zero
tatyana61 [14]

Hello from MrBillDoesMath!

Answer:

Cchoice B is the correct answer.

Discussion:

As stated by an earlier respondent, choice B is the correct answer. But why?

From the diagram, point B lies between  0 and 1 which means B is positive

From the diagram, point C lies between  -1 and -2 which means C is negative

The quotient of a negative number by a positive number is negative, giving the answer as choice c


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


8 0
3 years ago
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