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V125BC [204]
2 years ago
6

How do you find 5% of 250

Mathematics
1 answer:
Akimi4 [234]2 years ago
3 0

Answer:

250 \times  \frac{5}{100}  = 12.5

...................................................

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What's a range and domain?
Fofino [41]

Hey!!

Answer: The domain of a function is the complete set of possible values of the independent variable. In plain English, this definition means: The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

Hope this helps!

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7 0
3 years ago
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Trey runs each lap in 8 minutes. He will run at least 9 laps today. What are the possible numbers of minutes he will run today?
Yakvenalex [24]

Answer:

72\leqt

Solution:

8(9)\leq t

If he can run more than 9 laps today, but might not, then the total number of minutes can be more then or equal to nine laps.

3 0
2 years ago
When placed in liquid nitrogen, a chemical changes in temperature by -4.8°C
Lena [83]

Answer:

-2.4

Step-by-step explanation:

3 0
3 years ago
For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
laiz [17]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

8 0
3 years ago
Write the equation of the line that is parallel to y = -x – 5 and has a y-intercept at (0, 11).
FrozenT [24]

Answer:

y=-x+11

Step-by-step explanation:

We know that the new equation must be parallel to y=-x-5.

Therefore, since they are parallel, the slope of the new equation must be the same as the old.

The slope of the original equation is -1.

Therefore, the slope of our new equation is also -1.

We also know that it has a y-intercept at (0, 11).

And as determined earlier, it has a slope of -1.

So, we can use the slope-intercept form:

y=mx+b

Where m is the slope and b is the y-intercept.

We will substitute -1 for m and 11 for b. Thus, our equation is:

y=-x+11

8 0
3 years ago
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