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natka813 [3]
2 years ago
9

a taxi charges $2 per mile. there is also a $3 callout charge. how is distance related to cost. can you write an equation?​

Mathematics
1 answer:
elixir [45]2 years ago
5 0

Answer:

y= 3$ + x km * 2$

Step-by-step explanation:

since the callout price is 3$ you are gonna pay at least this much.. and then for every km/mile you will pay 2$.

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80 x 25 = n<br> Expanded form <br> 80 x ( ) <br> Partial product <br> 80 x 20=<br> 80 x 5 =
defon

9514 1404 393

Answer:

  2000

Step-by-step explanation:

Expanded form:

  80 × (20 + 5)

Partial products:

  80 × 20 = 1600

  80 × 5 = 400

Sum of partial products: 1600 + 400 = 2000.

8 0
3 years ago
Write the slope-intercept form of the equation of each line given the slope and y-intercept.
saul85 [17]

Answer:

4b. −6x + y = −4

4a. 7x + 4y = −12

3b. y = ½x + 3

3a. y = −6x + 5

2b. y + 2 = −⅔(x + 3)

2a. y - 3 = ⅘(x - 5)

1b. y = -x + 5

1a. y = 5x - 3

Step-by-step explanation:

4.

Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:

b.

2 = 6[1] + b

6

−4 = b

y = 6x - 4

-6x - 6x

_________

−6x + y = −4 >> Standard Equation

a.

4 = −7⁄4[-4] + b

7

−3 = b

y = −7⁄4x - 3

+7⁄4x +7⁄4x

____________

7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]

4[7⁄4x + y = −3]

7x + 4y = −12 >> Standard Equation

__________________________________________________________

3.

Plug both coordinates into the Slope-Intercept Formula:

b.

5 = ½[4] + b

2

3 = b

y = ½x + 3 >> EXACT SAME EQUATION

a.

−1 = −6[1] + b

−6

5 = b

y = −6x + 5

* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].

__________________________________________________________

2.

b. y + 2 = −⅔(x + 3)

a. y - 3 = ⅘(x - 5)

According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.

__________________________________________________________

1.

b. y = -x + 5

a. y = 5x - 3

Just write out the Slope-Intercept Formula as it is given to you.

I am joyous to assist you anytime.

3 0
3 years ago
Find the total cost : $20 meal; 9% tax on meal; 20% tip on meal​
Mrac [35]

Answer:

the meal cost $25.8 in total.

Step-by-step explanation:

9% of 20 is 1.8

20% of 20 is 4

20 + 1.8 + 4 = 25.8

May I have brainliest please? :)

3 0
3 years ago
Select all the values equal to 3/5
Novosadov [1.4K]

Answer:

B:

Step-by-step explanation:

brainliest pls

4 0
3 years ago
Read 2 more answers
In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
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