To find the rate, you must divide the distance traveled by the time it took.
17.5 m is the distance while time it took was 5 seconds.
So,
17.5 ÷ 5 = 3.5 m/s
The rate of the anchor is 3.5 m/s
Note: I did not ignore the negative sign in the distance but rather acknowledged it as a magnitude. This meant that the anchor was dropping down instead of going up.
Answer:
Chill is this a multiple choice?
Answer:
3 seconds
Step-by-step explanation:
16 = 160 - 16t²
16t² = 144
t² = 9
t = 3
THe LCD is x(x^2 - 4)
so multiplying through by this we get:-
2x(x + 2) + 7x = 5(x^2 - 4)
2x^2 + 4x + 7x = 5x^2 - 20
3x^2 - 11x - 20 = 0
(3x + 4)(x - 5 ) = 0
so x = 5 , -4/3
Its the second choice
If you were to make your own measurements, your significant digits should include all of the measurable digits (the digits that correspond to the marks on the ruler) as well as one estimated position beyond the smallest measureable digit (the 5 in 3.5 cm, and the 2 in 3.52 cm).
