Answer:
A right triangle can be considered as a special type because the relationship of its sides can be described using the hypotenuse formula: c^2 = a^2 + b^2 or c^2 = x^2 + y^2 where, c is the hypotenuse of the triangle and is the side opposite to the 90° angle while a and b are the sides adjacent to the 90° angle.
In the problem statement, we are given that one of the side has a measure of 2 = x, while the hypotenuse is 5 = c, therefore calculating for y: y^2 = c^2 – x^2 y^2 = 5^2 – 2^2 y^2 = 21 y = 4.58
Explanation:
The natural number is the number before the decimal. Therefore the answer is: y = 4
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<span>Answer:
The carbons on the closures are sp² hybridized, with a p-orbital for the 'second' bond in the twofold bond with their neighboring carbons.
They have those sp² orbitals covering with the s from the hydrogen, and they have a p covering in the pi bond with the neighboring carbon. They likewise have a sigma bond with the neighboring carbon I'll get to.
The center carbons each have two pi bonds with their neighbors, leaving sp hybridiaztion for the rest. So they have sp/sp² with the end carbons, and sp/sp with each other. (What's more, they likewise have p/p in the pi bonds).
So the total list is:
s/sp²
p/p
sp/sp²
sp/sp</span>